PAT-Advanced-1012. The Best Rank

2015/11/12  我的解答使用了不稳定的快排来实现基数排序,待修复

To evaluate the performance of our first year CS majored students, we consider their grades of three courses only: C – C Programming Language, M – Mathematics (Calculus or Linear Algebra), and E – English. At the mean time, we encourage students by emphasizing on their best ranks — that is, among the four ranks with respect to the three courses and the average grade, we print the best rank for each student.

For example, The grades of C, M, E and A – Average of 4 students are given as the following:

Then the best ranks for all the students are No.1 since the 1st one has done the best in C Programming Language, while the 2nd one in Mathematics, the 3rd one in English, and the last one in average.

Input

Each input file contains one test case. Each case starts with a line containing 2 numbers N and M (<=2000), which are the total number of students, and the number of students who would check their ranks, respectively. Then N lines follow, each contains a student ID which is a string of 6 digits, followed by the three integer grades (in the range of [0, 100]) of that student in the order of C, M and E. Then there are M lines, each containing a student ID.

Output

For each of the M students, print in one line the best rank for him/her, and the symbol of the corresponding rank, separated by a space.

The priorities of the ranking methods are ordered as A > C > M > E. Hence if there are two or more ways for a student to obtain the same best rank, output the one with the highest priority.

If a student is not on the grading list, simply output "N/A".

Sample Input

Sample Output


测试点2一直不过,重新看了一遍示例数据,还以为是因为平均分要四舍五入的问题(310103 82 87 94 88),然而修改后还是不过……

后来,后来纠结了半天,才发现并列排名的坑……并列排名有的是不占名次的,而这道是占名次的(生活中一般都是占名次的吧)……果然好久没看到有排名的成绩单之类的东西后,这些东西都淡忘了……(⊙﹏⊙)

代码如下:

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